Question

if x+y=4 then find the value of x cube+ y cube +12xy-64.

Answer 1

Given x + y = 4

On cubing both sides, we get

(x+y)^3 = 4^3

x^3 + y^3 + 3xy(x+y) = 64

x^3 + y^3 + 3xy(4) = 64

x^3 + y^3 + 12xy = 64

x^3 + y^3 + 12xy - 64 = 0.


Hope this helps!

Answer 2

Plz refer the above attachment for the answer.

Hope it helps you :)

Regards,
Shobana