if x2-6x-1=0 find x3-1/x3
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Answer :
x³ - 1/x³ = 234
Solution :
- Given : x² - 6x - 1 = 0
- To find : x³ - 1/x³ = 0
We have ,
=> x² - 6x - 1 = 0
=> x² - 1 = 6x
=> (x² - 1)/x = 6
=> x²/x - 1/x = 6
=> x - 1/x = 6
Now ,
Cubing both the sides , we get ;
=> (x - 1/x)³ = 6³
=> x³ - (1/x)³ - 3•x•(1/x)•(x - 1/x) = 216
=> x³ - 1/x³ - 3•1•6 = 216
=> x³ - 1/x³ - 18 = 216
=> x³ - 1/x³ = 216 + 18
=> x³ - 1/x³ = 234
Hence ,
x³ - 1/x³ = 234
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