Question

if y=2√x then dy/dx is​

Answer 1

Step-by-step explanation:

• GIVEN
• y=^x
• log y=^x log n
• 1dy upon y dx = ^x upon x +log n×1 upon2^n
• dy upon dx = y ( 2 ^x +^xlog n upon 2
• = y upon 2^x
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