If z=re^i theta then the value of modulus of e^iz
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Answer:
e^(-rsin1)
Step-by-step explanation:
Hi,
Given z = re^i
e^iz = e^(i*re^i)
But, e^iФ = cosФ + i sinФ, so
e^iz = e^ir(cos1 + isin1)
=e^(ircos1 - rsin1)
e^(-rsin1). e^(ircos1)
Modulus of e^iz will be = |e^(-rsin1). e^(ircos1)|
= e^(-rsin1) , since |e^(ircos1)| = 1.
Hope, it helps !
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