Question

If zeroes of the polynomial 6x²+4x+2α, are β and 1/α, then find α.

Answer 1

6x2+x−2=0

6x2+4x−3x−2=0

2x(3x+2)−(3x+2)=0

which gives us two equations,

2x−1=0=>x=1/2(alpha)

3x+2=0=>x=−2/3(beta)  

So, the value of alpha/beta and beta/alpha will be -3/4 and -4/3, adding both of them gives the solution as -25/12.