Question

ifx:y6:11,find(8x-3y):(3x+2y)

Answer 1

$\frac{x}{y} = \frac{6}{11}$
multiply both sides by 8/3
hence
$\frac{8x}{3y} = \frac{48}{33}$
by componendo dividendo
$\frac{8x + 3y}{8x - 3y} = \frac{48 + 33}{48 - 33} \\ = \frac{81}{15} = \frac{27}{5}$
hence by invertendo
$\frac{8x - 3y}{8x + 3y} = \frac{5}{27}$