Question

ii) In A ABC, angle B = 90°,angle C = 30°
AB = 6cm then find AC.​

Answer 1

Answer:

I think it's 12

tan30° = 1/✓3 = 6/BC

BC = 6✓3

sin60° = BC/AC = ✓3/2 = 6✓3/AC

AC = 12

Answer 2

Answer:

AC= 12cm

Step-by-step explanation:

Given in a right angled triangle, ΔABC

∠B= 90° and ∠C= 30°

AB = 6cm

and let us assume, AC = x cm

From the attached figure it's clear that hypotenuse  has to be found.

Apply sin(∠C) = $\frac{AB}{AC}$

(∵ sine of an angle is ratio of opposite side of the angle over the hypotenuse of the triangle).

sin(∠C)= sin(30°)= 6/x

               x= 6/ sin(30°)

               x= 6/(0.5)           ( ∵sin(30°) =1/2 or 0.5)

             ∴ x= 12 cm

Therefore, hypotenuse AC= 12cm