Math, asked by khusjiya39, 8 months ago

Il Solve the word problems
1.Convert 54 km/hr into m/s.
2.Calculate Time-period of a simple pendulum if it takes 72 seconds to
complete 24 oscillations.(Time period of the pendulum Time taken/Number of
Oscillations)
3.A train is travelling at a speed of 100 km/hr. How long will it take to complete a
journey of 500 km without stopping in between?
4.Ramesh takes 15 minutes to reach market from his house on this cycle. If the
speed of his cycle is 4 mis.Calculate the distance between his house and
market​

Answers

Answered by Scieinstein
2

Answer:

1. 15 m/s

2. 3 s

3. 5 hr

4. 3.6 km

Step-by-step explanation:

1. Required speed = 54× 5/18 m/s

= 3 × 5 m/s

= 15 m/s

2. Required time period = 72/24 s

= 3 s

3. Required time taken = Distance/speed

= 500 km/ 100 km/hr

= 5 hr

4. Required distance = speed × time

= 4 m/s × 15 × 60s

= 60 × 60 m

= 3600 m = 3.6 km

Answered by pranavshah
0

Answer:

Answer:

1. 15 m/s

2. 3 s

3. 5 hr

4. 3.6 km

Step-by-step explanation:

1. Required speed = 54× 5/18 m/s

= 3 × 5 m/s

= 15 m/s

2. Required time period = 72/24 s

= 3 s

3. Required time taken = Distance/speed

= 500 km/ 100 km/hr

= 5 hr

4. Required distance = speed × time

= 4 m/s × 15 × 60s

= 60 × 60 m

= 3600 m = 3.6 km

Step-by-step explanation:

1. Required speed = 54× 5/18 m/s

= 3 × 5 m/s

= 15 m/s

2. Required time period = 72/24 s

= 3 s

3. Required time taken = Distance/speed

= 500 km/ 100 km/hr

= 5 hr

4. Required distance = speed × time

= 4 m/s × 15 × 60s

= 60 × 60 m

= 3600 m = 3.6 km

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