in a cyclic triangle ABCD twice the measure of angle A is thrice measure of angle C then find the measure of angle A
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In a cyclic quadrilateral the sum of opposite angles is equal to 180°.
So, In quad. ABCD angle A and angle C are opposite angles.
Therefore, A + B = 180°
And also, A.T.Q. A = 3 of C
so, let C be x then A will be 3x.
So, 3x + x = 180°
4x = 180°
x = 180°/4
x=45°
so, 3x = 45°×3=135°
Therefore, angle A = 135°
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