Math, asked by skumark325, 5 months ago

In a cylindrical
container, circular
discs are stacked.
The first disc is 1 cm
in thickness, the
second is 2 cm thick,
and consecutive
discs increase by 1
cm. If the cylinder is
2 m tall, what is the
maximum number of
discs that can be
completely
contained in it?​

Answers

Answered by sahibsaifi12291
2

Step-by-step explanation:

Circular discs 5 mm thickness, are placed one above the other to form a cylinder of curved surface area 462 sq cm. if the radius is 3.5 cm.

As per given the thickness of disc =5mm=

10

5

cm=0.5cm

Radius of disc =3.5 cm

Cuvered surface area of cylinder =462 sq cm

∴2πr=462cm

2

.......................................(1)

Let number of discs are x

The height of cylinder =h= thicknessofdisc×numberofdiscs=0.5x

∴2πr=2× 22 /×3.5×05x............................(2)

From equation (1) and (2) we get

∴2πr=2× 22/7×3.5×05x=462

→x= 2×22×3.5×0.5462×7

=42 discs

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