in a hot water heating system , there is a cylindrical pipe of length 35 m and diameter 10 cm . find the total radiating surface in the system.
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Answered by
23
Height of the pipe=35m
Radius of the pipe=10÷2=5cm=0.05m
Total radiating surface in the system=2πrh
=2×22/7×0.05×35
=2×22×0.05×5(as 7 got cut off with 35)
=44×0.25
=11 m².
Hope it helps you.....
Please mark as brainliest answer!!!
Radius of the pipe=10÷2=5cm=0.05m
Total radiating surface in the system=2πrh
=2×22/7×0.05×35
=2×22×0.05×5(as 7 got cut off with 35)
=44×0.25
=11 m².
Hope it helps you.....
Please mark as brainliest answer!!!
Answered by
1
HII GUYZZZ HERE IS UR ANSWER
Step-by-step explanation:
Surface area of radiating system is = 2πrh
2×22/7×0.05×35 ( as diameter is 10cm so radius is 0.05cm)
= 44×0.25{as 7 gets cancled with 35 and 0.05×5 = 0.25}
= 11m²
Hope it hepls u
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