Question

In a perfectly symmmetrical distributions, the mode and mean are 42 and 49 respectively. The approximate median of this distribution is....option are 47, 48,49,50

Answer 1

we know,
$\boxed{\boxed{\text{mode}\pm2\text{mean}=3\text{median}}}$

Given in a perfectly symmetrical distribution,
the mode = 42
and the mean = 49
we have to find approximate value of the median.
so, $\text{mode}\pm2\text{mean}=3\text{median}$

42 ± 2 × 49 = 3 × median

42 - 2 × 49 = 3 × median [ ignored ]

=> 42 + 2 × 49 = 3 × median

=> 42 + 98 = 3 × Median

=> 140/3 = median

median = 46.67 ≈ 47

hence, answer is option (a).