in a quadrilateral abcd if angle=60°and angle b:c:d are 2:3:7find angle d is
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Angle a=60°
Let angle b,c,d be 2x,3x,7x respectively.
Sum of all angles of a quadrilateral=360°
60+2x+3x+7x=360
12x=360-60
x=300/12
x=25
Angle d = 7x
=7x25
=175°
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Answer:
let angle B C & D be 2x,3x,7x simultaneously
sum of all angles of quadrilateral is 360°
<A+<B+<C+<D=360°
60°+2x+3x+7x=360
12x=300°
x=300/12
x=25°
<A=60°
<B=50°
<C=75°
<D=175°
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