In a quadrilateral ABCD sides AB= BC= CD and angle C=150° , angle B=90° then find angle D?
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Answer:
60 degree
Step-by-step explanation:
given:- AB=BC=CD
and C=150 degree
angle B=90degree
Find:-angle D is =?
Now,
let angle D be x
and also Angle A be x
we know that,
the sum of quadrilateral is =360
<A+<B+<C+<D=360
=>X+90+150+X=360
=>2x+240=360
=>2x=360-240
=>2x=120
=>x=120/2
=>x =60°
Hence,<A=60°,<B=90°,<C=150°and <D=60
hope this will be helpful for you
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