Question

In a right angle triangle ABC with right angle at B ,in which a = 24 units , b = 25 units and angle BAC = Theta , then find cos theta and tan theta

Answer 1

AB=24,AC=25,THEREFORE BC=√25²-24²=√49=7

Now
Cos∆=AB/AC
=>COS∆=24/25
TAN∆=BC/AC
=>TAN∆=7/25
Where. ∆=theta ( suppose )

Answer 2

Answer:

Given: <BAC = θ

Let: 'a' be BC

       'b' be AC

∴ By Pythagoras theorem,

= (AC)² = (AB)² + (BC)²

= (AB)² = $\sqrt{AC^2+BC^2}$

= (AB)² = $\sqrt{25^2-24^2}$

           = $\sqrt{625-576}$

           = √49 = √7² ⇒ 7

⇒ cosθ = Adjacent/Hypotenuse = AB/AC = 7/25

⇒ tanθ = Opposite/Adjacent = BC/AB = 24/7