Math, asked by Rytpratisayhitadee, 1 year ago

In a right angled triangle pqr,pr is the hypotenuse and other two sides are of length 3cm and 4cm. X is a point outside the triangle such that px=12cm and xr = 13cm.find the measure of angle xpr

Answers

Answered by Golda
19
Solution:-
It is given that the hypotenuse is PR and other sides are 3 cm and 4 cm respectively.
So, according to Pythagoras Theorem,
Hypotenuse² = Base² + Perpendicular²
⇒ H² = (3)² + (4)²
⇒ H² = 9 + 16
⇒ H² = 25
⇒ H = 5 cm or side PR = 5 cm.
So, in the triangle XPR,
PR = 5 cm, PX = 12 cm and XR = 13 cm
5, 12 and 13 form a pythagorean Triplet, where XR will be hypotenuse.
That means angle opposite to the hypotenuse (XR) will be a right angle.
So, measure of the angle XPR is 90°.
Attachments:
Answered by midhun9918
3

Solution :

It is given that the hypotenuse is PR and other sides are 3 cm and 4 cm respectively.

So, according to Pythagoras Theorem,

Hypotenuse² = Base² + Perpendicular²

⇒ H² = (3)² + (4)²

⇒ H² = 9 + 16

⇒ H² = 25

⇒ H = 5 cm or side PR = 5 cm.

So, in the triangle XPR,

PR = 5 cm, PX = 12 cm and XR = 13 cm

5, 12 and 13 form a pythagorean Triplet, where XR will be hypotenuse.

That means angle opposite to the hypotenuse (XR) will be a right angle.

So, measure of the angle XPR is 90°

Hope it helps .....

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