In a SN2 substitution reaction of the type
R - Br + Cl⁻ □(→┴DMF ) R - Cl + Br⁻
which one of the following has the highest relative rate ?
(a) CH₃ – CH₂ – CH₂Br (b) CH₃ - CH - CH₂Br
|
CH₃
CH₃
|
(c) CH₃ - C - CH₂Br
|
CH₃
(d) CH₃CH₂Br
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Following which has the highest relative rate is :
Reaction : R - Br + Cl⁻ □(→┴DMF ) R - Cl + Br⁻
• Already given that above reaction is SN2 type.
(a) CH₃ – CH₂ – CH₂Br ( bromopropane )
(b) CH₃ - CH - CH₂Br ( 1-bromo-2-methyl propane )
|
CH₃
CH₃
|
(c)CH₃ - C - CH₂Br (1-bromo-2,2-dimethyl propane)
|
CH₃
(d) CH₃CH₂Br ( 1-bromo ethane )
• Increasing order of steric hindrance in the given compound is as below :
(c) > (b) > (a) > (d)
• Therefore, Increasing order of SN2 reaction is :
(c) < (b) < (a) < (d)
• (d) i.e 1-bromo ethane, has the highest relative rate
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