Question

In a triangle ABC, if 10a=b=5c and S=a*a,
Then find the value of a

Pls tell this question

Answer 1

Howdy!!

your answer is ----

according to given condition

10a = b ......(1)

and 5c = 10a

=> c =>2a ..... (2)

a×a = a+b+c/2

=> a^2 = a + 10a + 2a/2 (from 1,2)

=> a^2 = 13a/2

=> a = 13/2 = 6.5

hope it help you

Answer 2

hey here is ur answer..

given :: s= a*a and
10a= b = 5c
on solving this we have b= 10a and c = 2a
now
a+b+c/2= a^2
a+10a+2a= 1a^2
13a= 2a^2
13/2 = a
so a= 6.5

hope it helps you !!!