Question

In a typical Indian Bugghi (a luxury cart drawn by horses), a wooden plate is fixed on the rear on which one person can sit. A bugghi of mass 200 kg is moving at a speed of 10 km/h. As it overtakes a school boy walking at a speed of 4 km/h, the boy sits on the wooden plate. If the mass of the boy is 25 kg, what will be the plate. If the mass of the boy is 25 kg, what will be the new velocity of the bugghi?

Answer 1

Explanation:

Bugghi mass, $m_1$ = 200 kg  

Bugghi velocity, $v_1$ = 10 km / h

Boy mass, $m_2$ = 2.5 kg  

Boy velocity, $v_2$ = 4 km / h.

When we find Buggie and boy as a system, the total momentum will remain constant after the sitting proc-ess before the sitting process.

$m_1v_1 = m_2v_2 = (m_1+m_2) v$

200 x 10 + 25 x 4 = (200+25) v

2000 + 100 = (200+25) v

2100 = (225) v

$v=\frac{2100}{225}$

$v=\frac{28}{3}$

$v = 9.3 km/hr$