In ∆ ABC, BC=AB and <B=80° then find <A
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Answer: BC=AB
⇒∠A=∠C (As angles opposite to equal side are equal)
let the angles be x each.
Now by angle sum property
∠A+∠B+∠C=180
∘
⇒x+80
∘
+x=180
∘
⇒2x=180
∘
−80
∘
⇒2x=100
∘
⇒x=50
∘
∴∠A=50^0
hope it helps
tqm///.
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