In an examination,Amit gets 56% of total marks and failed by 110,while Sumit gets 74% of the total marks and gets 34bmore than the passing mark.find the total marks and those necessary for passing.
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let passing marke is 100%
56% + 110 = 74% - 34=== passing mark
74% - 56% = 110 +34
18% = 144
then 100% = (144/18)×100
8×100 = 800
56% + 110 = 74% - 34=== passing mark
74% - 56% = 110 +34
18% = 144
then 100% = (144/18)×100
8×100 = 800
s7388:
what to understand from 34b mark.
now it is correct
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Given :
In an examination,Amit gets 56% of total marks and failed by 110,while Sumit gets 74% of the total marks and gets 34bmore than the passing mark.
To Find :
find the total marks and those necessary for passing.
Solution:
Let the total marks be x
So,,Amit gets 56% of total marks and failed by 110,
Amit gets marks = 0.56x
Passing marks = 0.56x+110
Sumit gets 74% of the total marks and gets 34bmore than the passing mark.
Sumit gets marks = 0.74x
Passing marks =0.74x-34
So,0.56x+110=0.74x-34
144=0.18x
x=800
Hence The total marks is 800
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