in an isosceles triangle, the base angle are equal ,the vertex angle is 40degre .what are the base angles of the triangle.
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The base angles of the triangle are 40°
Step-step explanation
As the base angles of any triangles are equal.
So let the base angles be x
∴ x +x + 40° = 180° ( sum of all angles of a triangle= 180°)
∴ 2x + 40° = 180°
∴ 2x = 180 -40
∴ 2x = 140
∴ x = 140/2
∴ x = 70
∴The base angles of the triangle are 40°
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