In an L-C-R ereis circuit R=150Omega, L=0.0750 H and C=0.0180muF . The source has voltage amplitude V=150V and a frequencey equal to the resonacne frequency of the circuit. (a) What is the power factor ? (b) What is the average power delivered by the source? (c) The capacitor is replaced by one with C=0.0360muF and the source frequency is adjusted to the new resonance value. Then, what is the average power delivered by the source?
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Answer:
averge power delivered by the source=0.12345...
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Thus the power delivered by the source is 75 W
Explanation:
Given data:
- Resistance "R" = 150 Ω
- Inductance "L" = 0.0750 H
- Capacitance "C" = 0.0180 muF
- voltage V = 150 V
Solution:
(a) At resonance frequency,
XL = XC
Z = R and power factor cosϕ = R Z = 1.0
(b) P = V^2rms / R = (150/√2)^2 / 150 = 75 W
(c) Again P = V^2 rms / R = 75 W.
Thus the power delivered by the source is 75 W
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