Question

In Figure 5, a triangle PQR is drawn to circumscribe a circle of radius 6 cm such that the segments QT and TR into which QR is divided by the point of contact T, are of lengths 12 cm and 9 cm respectively. If the area of ΔPQR = 189 cm² , then find the lengths of sides PQ and PR.

Answer 1

TR = XR = 9 Cm [ tangent to a circle from the same external point]
QT=QY= 12 Cm
PY =PX = y cm
1/2 ×PT ×(12+9)=189
PT =18
QP=√{(18)²-(12)²}=6√(5)
PR = √{(18)²-(9)²}=9√(3)

Answer 2

Answer:

attached file

Step-by-step explanation:

split triangle into 3 triangles and solve by adding those 3 areas