In how many ways can 5 boys and 3 girls be arranged so that no two girls may sit
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I think the answer is there are 8-9 ways.
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5 boys can be arranged in 5 places in 5! Ways.
In between, beginning and ending there are 6 places. 3 girls can be arranged in 6 places in P(6,3) ways.
By fundamental principle the number of possible arrangements =5!*P(6,3) ways
=14400
In between, beginning and ending there are 6 places. 3 girls can be arranged in 6 places in P(6,3) ways.
By fundamental principle the number of possible arrangements =5!*P(6,3) ways
=14400
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