Question

In random mating population of 1200, frequency of dominant allele is 0.6 .what will be the frequency of heterozygous individuals in population?

Answer 1

the dominant frequency is 0.6
so, the recessive frequency is 1-0.6=0.4
according to the genetic formula p²+q²+2pq=1, the heterozygous frequency is 0.48
so, no. of heterozygotes in the population is 0.48x1200
                                                                     =576 ppl.
hope it helpsss.....