in the angle of depression of a Boat from a 50m high Bridge is 30° then horizontal distance of the boat from the bridge is
Answers
Answered by
38
Answer: Distance of the boat from the bridge is 50√3 = 50*1.73 = 86.5 metres
Step-by-step explanation:
Let the height of the bridge be “x” metres = 50 m
Let the distance between the bridge and the boat be “y” metres
Angle of depression is 30 degrees
=> angle of elevation form boat to the highest point of the bridge = 30 degrees
Tan 30° = height of the bridge / distance between bridge and boat
=> (1 / √3) = x / y
=> 1 / √3 = 50 / y
=> y = 50√3
Distance of the boat from the bridge is 50√3 = 50*1.73 = 86.5 metres
Please brainlist my answer, if helpful!
Answered by
4
Answer:
plz mark me as brainlist answer
Attachments:
Similar questions