in the fig. AB is chord to the small circle and a tangent to the small circle if AB=8cm prove that Area of the shaded portion is 16pai cm
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R be the radius of big circle
x be the small one
Acc to phythagors th.
x=sqrt(R2 - 16)
And when you find the area of both the circles.... You'll find that the area of inner circle is pie x 16
Then the required area will be pi x 16
x be the small one
Acc to phythagors th.
x=sqrt(R2 - 16)
And when you find the area of both the circles.... You'll find that the area of inner circle is pie x 16
Then the required area will be pi x 16
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