Question

. In the Fig., ABC is a right triangle
right-angled at B. The length of AC is
(a) 9 cm
(6) 12 cm
(c) 11 cm
(d) 10 cm
AB 6 cm
BC 8 cm
AC ?​

Answer 1

Answer:

$by \: phytagoras \: theorem \\ {h}^{2} = {b}^{2} + {a}^{2} \\ a {c}^{2} = (8 {)}^{2} + (6 {)}^{2} \\ a {c}^{2} = 64 + 36 \\ ac = \sqrt{100} = 10$

Therefore, AC is 10cm

Answer 2

(d) 10 cm

Step-by-step explanation:

QUESTION :-

ABC is a right triangle at B. The length of AC is

(a) 9 cm

(b) 12 cm

(c) 11 cm

(d) 10 cm

Lengths of

AB = 6 cm

BC = 8 cm

___________________________

SOLUTION :-

A.T.Q.,

We can say that,

AB = perpendicular height

BC = base

AC = Hypotenuse

We know that,

Pythagoras theorem says,

(Hypotenuse)² = (Base)² + (Height)²

=> AC² = BC² + AB²

=> AC² = 8² + 6²

=> AC² = 64 + 36

=> AC² = 100

=> √AC² = √100

=> AC = ±10

Length cannot be negative,

So,

the length of AC = 10 cm (d)

__________________________

Hope it helps.

#BeBrainly :-)