Question

In the figure AB,BC, CD and
DE are linesegments and AB is parallel to CD Find the value of x
​

Answer 1

Step-by-step explanation:

Given:

Angle ABC=40°

AB||CD

Angle ECD= Angle ABC =40° {Alternate.

angle}

As we know that,

Sum Of all angles of Δ=180°

Angle ECD+ Angle CED+ Angle EDC=180°

40°+x+50°=180°

90°+x°=180°

x°= 180°-90°

x°=90°

Answer 2

Answer:

ABC= 40

AB//CP

ECD=ABC(40°)

ONE OF THE SIDE OF TRIANGLE =40°(ALTERNATE ANGELA)

40+50+x=180

90+x=180

x=180-90

x=90°