Math, asked by akshitsharma7334, 1 year ago

In the figure area of triangle abd is 10 sq. cm and area of triangle adc is 12 sq. cm. Find bd:dc and if bd=5cm then find dc


amitnrw: Missing Figure

Answers

Answered by RanaMuneeb
70

Answer:

Hi

Find the answer in the image.

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Answered by amitnrw
10

Given : Area of ΔABD = 10 cm²  and Δ ACD is 12 cm²

To Find : BD : DC

if BD = 5 cm then DC

Solution:

Draw AM ⊥ BC

area of triangle = (1/2) * base * height

Area of  ΔABD = (1/2) * BD * AM  = 10

Area of  ΔACD = (1/2) * CD * AM  = 12

=> BD/CD = 10/12

=> BD/CD = 5/6

=> BD : CD = 5 :6

if BD = 5 then CD = 6 cm

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