In the figure area of triangle abd is 10 sq. cm and area of triangle adc is 12 sq. cm. Find bd:dc and if bd=5cm then find dc
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Given : Area of ΔABD = 10 cm² and Δ ACD is 12 cm²
To Find : BD : DC
if BD = 5 cm then DC
Solution:
Draw AM ⊥ BC
area of triangle = (1/2) * base * height
Area of ΔABD = (1/2) * BD * AM = 10
Area of ΔACD = (1/2) * CD * AM = 12
=> BD/CD = 10/12
=> BD/CD = 5/6
=> BD : CD = 5 :6
if BD = 5 then CD = 6 cm
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