Question

in the figure quadratic ABCD is circumscribing a circle with Centre 0 and a d parallel to ab if radius of circle is 10 then the value of Axis​

Answer 1

Step-by-step explanation:

Let O be the mid point,

As = Ap ( tangent to the given circle)

and since L SAp is 90°

As = OP = Ap = 10cm ( radius)

Now, Let t be the point where Ap meets Cq

and we know that Cq = PR = 27 (tangent)

and Ct = 38 ( given in the fig)

» Cq + qt = 38

» 27cm + qt = 38cm

» qt = 38cm-27cm = 11cm

and now tp = tq ( tangent)

tp = 11cm

So to find x , i.e Apt

we have Apt = Ap + pt

= 10cm + 11cm = 21 cm