In the given diagram of a simple pendulum, the time taken by the bob to
move from X to Z is t, and from Z to O is 't. The time period of this simple
pendulum is-
X
Z
(t,+)
(1,-
+
2
is
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6
- 2(t1+t2) is the correct answer
Answered by
1
Answer: I think the answer is 4(t1+ t2), as t(XOYOX) is time period. Pendulum requires same time to cover XO to OY and XZ + XO = XO
the time of the simple pendulum is 4(t1+t2)
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