Question

In the given figure chords AB and CD are interesting at P. AB = 10cm. PB = 4cm. and PD = 3cm. a) what is the length of PA ? b) Find the length of PC ?

5 points

what is the length of PA ? b) Find the length of PC ?
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Answer 1

Answer:

Two chords AB & CD intersecting inside a circle at point P follows the relation : PA x PB = PD x PC => PD = PA x PB/PC = 8 x 2/4 = 4 cms :-)

Answer 2

Given:

The chords AB and CD are interesting at P.

AB = 10cm.

PB = 4cm.

PD = 3cm.

To find :

• The length of PA.
• The length of PC.

Solution:

Step 1 of 2:

If the chords AB and CD are interesting at P, then

PA × PB = PD × PC

PA = AB - PB

To find PA substitute AB and PB values.

PA = 10 - 4

PA = 6cm

Step 2 of 2:

To find PC substitute PA, PB and PD values.

PA × PB = PD × PC

6 × 4 = 3 × PC

24 = 3  × PC

PC =$\frac{24}{3}$

PC = 8cm

Final answer:

• The length of PA is 6cm.
• The length of PC is 8cm.