In the given figure o and o' are the centers of two circles intersecting at C and B . ACD is a straight line . Find x °
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hey friend x°=130° as OBO'D Is a cyclic quadrilateral and In a cyclic quadrilateral opposite sides add upto 180°
Step-by-step explanation:
angle
angle AOB =130° so angle COB=180°-130°=50°
Angle COB + Angle x = 180°( cyclic quadrilateral)
50°+x=180° so x= 130°
hope it helps you
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