in triangle abc angle b = 90 evalute cosecAcosC -sinAsecC
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Answer:
In triangle ABC
angle (A + B + C) = 180
A + C = 180-90
A + C = 90
A= 90-C
cosecAcosC-sinAsecC
cosecA= sec(90-A)
cosecA= sec(90-(90-C)=secC
similarly
sinA=cos(90-A)=cos(90-(90-C)=cosC
cosecAcosC-sinAsecC
secC×1/secC-1/secC×secC =1-1=0
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