Question

In triangle ABC, DE is drawn parallel to AB, If AD=2x, DC=x+3, BE= 2x-1 , CE= x then find value of x

Answer 1

By thales theorem DE/AD=CE/BE         =x+3/2x=x/2x-1 =(x+3)(2x-1) = 2x square =2x square -x +6x -3 -=2x square = 5x-3=0 i.e x=3/5