Math, asked by samarthsingh516, 5 months ago

integral upper limit π and lower limit 0 √1-x/1+x dx =?

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Answered by govind1021

0

Answer:

π-π^2\2

- 0 +0/0 ( which is undefined .)

Step-by-step explanation:

Final answer is : π-π^2\2 .

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