integrate the following function
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Given Integration sin^3(x)cos^3(x) dx can be written as
Integration sin^3(x)(1 - sin^2(x))cos(x)dx
Let u = sin(x) and du = cos(x)dx
Integration u^3(1 - u^2)du
Integration u^3 - u^5 du
= u^4/4 - u^6/6 + c (from (1))
= sin⁴(x)/4 - sin^6 (x)/6 + c (or) 1/4 sin^4x - 1/6 sin^6x + c.
Integration sin^3(x)(1 - sin^2(x))cos(x)dx
Let u = sin(x) and du = cos(x)dx
Integration u^3(1 - u^2)du
Integration u^3 - u^5 du
= u^4/4 - u^6/6 + c (from (1))
= sin⁴(x)/4 - sin^6 (x)/6 + c (or) 1/4 sin^4x - 1/6 sin^6x + c.
devjoshi28:
thank you.!!
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