Question

iron (ll) sulphide reacts with dilute sulphuric acid to give a solution of iron (ll) sulphite. on crystallisation the solution yield crystals of FeSo4.7H2O. how many grams of these crystals will be obtained if we star with 88g of iron(ll) sulpide?

Answer 1

Iron (ll) sulphide reacts with dilute sulphuric acid to give a solution of iron (ll) sulphate.

FeS + H2SO4 ----> FeSO4.7H2O


mass of Fes = 56 + 32 = 88 g 

mass of H2SO4 = 98 g 

mass of FeSO4.7H2O = 278g 

its simple.... if we take 88g of Fes then iron sulphide will form in the amount of "278g"