LCM of two numbers is 180, their HCF is 12,then the sum of the two numbers is
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Given : LCM of two numbers is 180, their HCF is 12
To Find : sum of the two numbers
Solution:
Assume two numbers are
12A and 12B
where A & B are co prime
Sum = 12A + 12B
= 12(A + B)
12A x 12B = LCM x HCF
=> 12A x 12B = 180 x 12
=> AB = 15
=> A = 1 , B = 15
or A = 3 , B = 5
12 , 180 => Sum = 192
36 , 60 => Sum = 96
Sum of Two numbers is 96 or 192
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