Question

lenths of two rods are(10+-0.2)m and (12+-0.3) m find the length of the two rods with error limit​

Answer 1

Answer:

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Explanation:

Given l

1

=1.8±0.2

And, l

2

=2.3±0.1

⇒l=l

1

+l

2

=4.1m

Since, error is additive in nature, Δl=Δl

1

+Δl

2

=0.3m

So, combined length with error limits is (4.1±0.3)m