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The diameter of a metallic sphere
is 6cm. It is melted and drawn
a long wire having a wricula
kross sections of diameter as 0.2cm.
Find the length of wire
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Answer:
clearly, what will not change is mass or volume of the metal. we will proceed with volume
volume of sphere = (4/3)πr^3
= (4/3)*π*6^2
= 288π
cross section area of wire = πr^2
= π(0.2)^2
= 0.04π
let length of wire be L
volume of wire = 0.04πL
volume should be equal
0.04πL = 288π
L = 288/0.04
L = 7200 cm
L = 72 m
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