lim x tends to 0 (x²)/|x|
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Answer: The question is related to Limits and continuity
We have: lim x tends to 0 (x²)/|x|
Step-by-step explanation:
Step-1 : modulas of x i.e,|x| is a signum function
So it has two values
|X|= +x for x>0
-x for x<0
We will use
Lim x tends to 0+ (x²)/|x|
Which is equal to (x²)/+x
As x tends to zero the term will be equal to lim x tends to 0+ 0/0 form
In that case we use L-hospitals rule
Differentiate numerator and denominator seperately w.r.t x we get
Lim x tends to 0+ 2X/1
The answer is 0
Now lim x tends to 0- (x²)/|x|
Lim x tends to 0- (x²)/-x
Same rule applies here as well
So answer is 0 again
Now lim x tends to 0 (x²)/|x| = 0
Which implies that limit of the function exists..
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