Linear equation in two variable 6x+3y=6xy
2x+4y=5xy solving
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2
6x+ 3y= 6xy........(1).......×1
2x+4y= 5xy.............(2)....×3
By using elimination method
we get
6x+ 3y= 6xy
6x+8y= 10xy
Now on subtracting equations(2)-(1)
We get
-5y= -4xy
5/4= x
thus putting the value of x in equation (1)
we get
6(5/4)+3y= 6(5/4)y
30/4+3y= 30/4y
(30+12y)/4= 30/4y
30+12y= 30y
30= (30-12)y
30/18=y
y= 3/5
(^^)(^^)✌
2x+4y= 5xy.............(2)....×3
By using elimination method
we get
6x+ 3y= 6xy
6x+8y= 10xy
Now on subtracting equations(2)-(1)
We get
-5y= -4xy
5/4= x
thus putting the value of x in equation (1)
we get
6(5/4)+3y= 6(5/4)y
30/4+3y= 30/4y
(30+12y)/4= 30/4y
30+12y= 30y
30= (30-12)y
30/18=y
y= 3/5
(^^)(^^)✌
Answered by
0
6x+3y=6xy............(1)
2x+4y=5xy............(2)
from equation 1 and 2
12x+6y=12xy......... (equation 1×2)
12x+24y=30xy....... (equation 2×6)
(-) (-). (-)
______________
-18y=18xy
x= -18y/18y
x=-1
substitute the value of x in equation 1 or 2 you will get the value of Y
I think this will help you
2x+4y=5xy............(2)
from equation 1 and 2
12x+6y=12xy......... (equation 1×2)
12x+24y=30xy....... (equation 2×6)
(-) (-). (-)
______________
-18y=18xy
x= -18y/18y
x=-1
substitute the value of x in equation 1 or 2 you will get the value of Y
I think this will help you
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