Lt x tends to zero 1-cosmx/1-cosnx
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Hi !!!
We. know that 1 - Cos(mx) =. 2 Sin²(mx) / 2
and. 1 - Cos ( nx ) = 2 Sin² ( nx /2 )
Lt. Sin² ( mx / 2 ) /. Sin² ( nx / 2 )
x->0
Lt. ( mx / 2 )² / ( nx / 2 )²
x->0
m² / n²
Have a great day.
We. know that 1 - Cos(mx) =. 2 Sin²(mx) / 2
and. 1 - Cos ( nx ) = 2 Sin² ( nx /2 )
Lt. Sin² ( mx / 2 ) /. Sin² ( nx / 2 )
x->0
Lt. ( mx / 2 )² / ( nx / 2 )²
x->0
m² / n²
Have a great day.
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