Math, asked by thelegendgamerp7rt8q, 1 year ago

MATHS CLASS 10 CLICK ON THE PIS ABOVE ANSWER PLZ​

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Answered by Anonymous
1

Here is your answer ⤵⤵⤵⤵

Let √3 be a rational number

√3 = a/b ( where a & b are integers & b is not equal to 0)

squaring both sides

3= a²/b²

=> 3b² = a²

=> a² is divisible by 3

=> a is divisible by 3

a = 3c (where c is an integer)

squaring both sides

a²= (53c)²

a²= 9c²

also,

a² = 3b²

=> 3b² = 9c²

=> b² = 3c²

=> b² is divisible by 3

=> b is divisible by 3

which is a contradiction as a & b are Co prime integers.

=> Our assumption is wrong.

=> √3 is an irrational number.

HOPE IT HELPS YOU ☺☺ !!!


rutujatayade98: sry....bt i did't understand
thelegendgamerp7rt8q: my class 10 started 9 days ago
rutujatayade98: oh....my class 10 was overing on 22 march
thelegendgamerp7rt8q: bye guys
rutujatayade98: as your wish
thelegendgamerp7rt8q: oh my one just started
rutujatayade98: bye dear
rutujatayade98: gn sd tc
thelegendgamerp7rt8q: bye
thelegendgamerp7rt8q: good night
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