middle term of (x/3 -9y)^10
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Step-by-step explanation:
a = x/3 b = -9y n = 10 middle term: (n/2 + 1) = 6th term
x = 5
Tₓ₊₁ = ⁿCₓ aⁿ⁻ˣ bˣ
= ¹⁰C₅ (x/3)¹⁰⁻⁵ (-9y) ⁵
= - 252 x⁵ y⁵ (9/3)⁵
= - 252*243 x⁵y⁵
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