Chemistry, asked by shahvishakha9490, 9 months ago

निम्नलिखित मिश्रणों की pH परिकलित कीजिए
(क) 10 mL\quad of \quad0.2M Ca(OH)_2 + 25 mL \quad of\quad 0.1M HCl
(ख) 10 mL \quad of 0.01M H2_SO_4 + 10 mL\quad of \quad0.01M Ca(OH)_2
(ग) 10 mL \quad of \quad 0.1M H_2SO_4 + 10 mL\quad of \quad 0.1M KOH

Answers

Answered by bishnupriyarout6409
0

Answer:

I don't know the answer. So sorry.....

Answered by ankugraveiens
0

(क) - pH = 12.63

(ख) - pH = 7

(ग) - pH = 1.30

Explanation:

(क)   Ca(OH)_2  का  Meq. = 10 \times 0.2 \times 2 = 4

         HCl  का  Meq. = 25 \times 0.1 \times 1 = 2.5

       Ca(OH)_2  का शेष  Meq. = 4 - 2.4 = 1.5

         अब ,        Ca(OH)_2  का नार्मलता , N = \frac{1.5}{10+25} = \frac{1.5}{35} = 4.3 \times 10^{-2}

                 अर्थात  ,  [OH^-] = 4.3 \times 10^{-2} N

        इसलिए ,  pOH = 1.36    और  pH = 12.63

(ख)   H_2SO_4  का  Meq. = 10 \times 0.01 \times 2 = 0.2

       Ca(OH)_2  का  Meq. = 10 \times 0.01 \times 2 = 0.02

 चूकि विलयन तटस्थ है , इसलिए pOH = pH = 7

(ग)     H_2SO_4  का  Meq. = 10 \times 0.1 \times 2 = 2

        KOH  का  Meq. = 10 \times 0.1 \times 1 = 1

      H_2SO_4  का शेष  Meq.= 1

        अब ,        H_2SO_4  का नार्मलता ,  N =  \frac{1}{20} = 5 \times 10^{-2}

          इसलिए  ,  [H^+] = 5 \times 10^{-2} N  और  pH = 1.30

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