Normal water contains isotope of hydrogen 3 H tritum .it has half life of 12.3 years.determine the age of bottet of wine whose 3 H radiation is about 1/10
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Hey dear,
● Answer -
Age = 40.87 years
● Explaination -
# Given -
Let T be half life of tritium.
T = 12.3 years
A/A0 = 1/10
# Solution -
Equation of radioactivity -
A = A0 × 2^(-t/T)
Solving this for t,
t = T/0.693 ln(A0/A)
t = 12.3 / 0.693 × ln(10)
t = 17.75 × 2.303
t = 40.87 years
Therefore, the age of given bottle of wine is 40.87 years.
Hope this help you...
● Answer -
Age = 40.87 years
● Explaination -
# Given -
Let T be half life of tritium.
T = 12.3 years
A/A0 = 1/10
# Solution -
Equation of radioactivity -
A = A0 × 2^(-t/T)
Solving this for t,
t = T/0.693 ln(A0/A)
t = 12.3 / 0.693 × ln(10)
t = 17.75 × 2.303
t = 40.87 years
Therefore, the age of given bottle of wine is 40.87 years.
Hope this help you...
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